# Trigonometry Practice Paper : Advance maths important questions

Trigonometry Practice Paper : Advance maths important questions

Q361. If A = sinθ  + cos4 θ, for any value of θ, then value of A is

(a)

(b)

(c)

(d)

Q362. If sin θ + cosec θ = 2,then the value of sinθ  + cosec5 θ when 0° ≤ θ ≤ 90° , is

(a) 0

(b) 1

(c) 10

(d) 2

Q363.  If tan2 θ . Tan 4 θ  = 1, then the value of tan 3 θ is :

(a) √3

(b) 0

(c) 1

(d) 1/√3

Q364. If cosα + β = 2, then the value of tan3 α+ sinβ is :

(a) -1

(b) 0

(c) 1

(d)  1/√3

Q365. If  θ is a positive acute angle and tan 2 θ tan 3  θ= , then the value of  is

(a)  -1/2

(b) 1

(c) 0

(d) 1/2

Q366. In a right – angled triangle XYZ right  – angled at Y, if XY = 2√6 and XZ – YZ = 2, then sec X + tan X is

(a) 1/√6

(b)  √6

(c) 2√6

(d) √6/2

Q367. The minimum value of sin2θ + cos2θ + sec2θ +cosec2 θ+ tan2θ + cot2θ  is

(a) 1

(b) 3

(c) 5

(d) 7

Q368. If 2 sin  =  then the value of  is :

(a) -1

(b) 2

(c) 1

(d) 0

Q369. If cos θ + sec θ = 2, then value of cos6 θ + secθ

(a) 4

(b) 8

(c) 1

(d) 2

Q370. The numerical value is :

(a) 5

(b) 2

(c) 3

(d) 4

Q371. The numerical value of  is

(a) 0

(b) -1

(c) +1

(d) 2

Q372. .  If  the value of  is :

(a) 25/16

(b) 41/19

(c) 41/40

(d) 40/41

Q373. If tan 7 θ tan 2 θ = 1, then the value of tan 3 θ  is :

(a) √3

(b) -1/√3

(c)  1/√3

(d) -√3

Q374. The value of  is

(a) 4

(b) 1

(c) 3

(d) 2

Q375. If sec θ + tan θ = 2, then the value of sec θ is :

(a)  4/5

(b)  5

(c)  5/4

(d)  √2

Q376. If cosec θ – sin θ  = l and sec θ  – cos θ = m, then the value of l²m²(l² + m² + 3  ) is:

(a) – 1

(b) 0

(c) 1

(d) 2

Q377. If  = 1, then value of cot θ is:

(a) 1/2

(b) 1/3

(c)  3

(d)  2

Q378. If tan θ = 2, then value of  is

(a)  21/5

(b)  8/5

(c)  7/5

(d)  16/5

Q379. If tan θ + cot θ = 2, then the value of tan100 θ is

(a) 2

(c) 0

(c) 1

(d) √3

Q380.  is equal to

(a) 1-tan θ – cot θ

(b) 1+ tan θ – cot θ

(c) 1 – tan θ + cot θ

(d) 1 + tan θ  + cot θ

Q381. If sin θ + cosec θ = 2, then the value of sin9 θ  + cosec9 θ is:

(a) 3

(b) 2

(c) 4

(d) 1

Q382. If sec θ + tan θ = 2 +√5 , then the value of sin θ + cos θ is:

(a)   3/√5

(b)   √5

(c)   7/√5

(d)   1/√5

Q383. The value of (1+cot θ -cosec θ)(1+tan θ) is equal to

(a) 1

(b) 2

(c) 0

(d) -1

Q384. If tan θ + cot θ  = 2, then the value of tann θ+cotn θ(0° < θ< 90 °, n is an integer ) is

(a) 2

(b) 2”

(c) 2n

(d) 2n+1

Q385. If  then sin θ – cos θ is equal to

(a) x – y

(b) x + y

(c)

(d)

Q386. If x = a sec θ cos ø, y =  sec θ sin ø, z = c tan θ, then the value of  is:

(a) 1

(b) 4

(c) 9

(d) 0

Q387. If   then sin θ is equal to:

(a) 1/4

(b) 1/3

(c) 2/3

(d) 3/4

Q388. If cos x + cos2x = 1, the numerical value of (sin12x+3 sin10x+3 sin8x+sin6x-1) is:

(a) -1

(b) 2

(c) 0

(d) 1

Q389. If (1+sin α) (1+sin β) (1+sin γ) = (1-sin α )(1-sin β)(1-sin γ), then each side is equal to

(a) ±cos α cos β cos γ

(b) ±sin α sin β sin  γ

(c) ±sin α cos β cos  γ

(d) ±sin α sin β cos γ

Q390. The numerical value of     θ will be :

(a) 2

(b) 5

(c) 6

(d) 3

Q391.The value of is :

(a) 4

(b) -1

(c) 2

(d) 3

Q392. The value of 3(sin x – cos x)4 + 6(sin x + cos x)2 + 4 (sin6 x + cos6 x) is

(a) 14

(b) 11

(c) 12

(d) 13

Q393. The value of secθ  – 2tan2 θ is

(a) 4

(b) 1

(c) 2

(d) 0

Q394. If tan θ+ cos θ then the value of tan2 θ+cot2 θ is

(a) 2

(b) 1

(c) √2

(d) 0

Q395. The eliminant of θ from x cos θ – y sin θ= 2 and x sin θ + y cos θ = 4 will give

(a)  x² + y2 = 20

(b) 3x2 + y2 = 20

(c) x2 – y2 = 20

(d) 3x2 – y2 = 100

Q396. The value of  (sec2A-cosec2A)

(a) 1

(b) 3

(c) 2

(d) 1

Q397. The value of  is

(a) 1

(b) cot θ

(c) cosec θ

(d) tan θ

Q398. If cos θ + sin θ = √2cos θ  then cos θ – sin θ is

(a) √2tan  θ

(b) – √2 cos θ

(c) – √2 sin  θ

(d)  √2 sin θ

Q399. If cosθ  – sin4 θ = , then  the value of  1- 2 sin2  θ is

(a)   4/3

(b)   0

(c)    2/3

(d)   1/3

Q400.  The value of   is:

(a)   1/4

(b)   1

(c)   5/4

(d)  4/3

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