# SSC CGL Math Project 400 Questions :: Work And Time

SSC CGL Math Project 400 Questions :: Work And Time

**Work and Time**

**About Work and Time
**

I am posting 15 varieties questions on ” Work and Time” . This is considered a difficult chapter. Generally 2-3 questions can be asked in Tier 1 and 5-8 in Tier 2. This chapter will have direct link with other chapters like Pipes and Cistern and Work and Wages.

**Work and Time: Maths**

**Q1.**A can do a piece of work in 10 days and B can do it 20 days. How many days will both take together to complete the work?

**Q2.**A and B can do a work in 12 days, B and C in 15 days and C and A in 20 days. If A, B and C work together, they will complete the work in:

**Q3.**A and B can do a work in 18 and 24 days respectively. They worked together for 8 days and then A left. The remaining work was finished by B in:

**Q4.**A can do a piece of work in 12 days and B can do it in 18 days. They work together for 2 and then A leaves. How long will B take to finish the remaining work?

**Q5.**A and B working separately can do a piece of work in 10 days and 15 days respectively. If they work on alternate days beginning with A, in how many days will the work be completed

**Q6.**If 6 men and 8 boys can do a piece of work in 10 days and 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys to do the same type of work will be:

**Q7.**5 persons can prepare an admission list in 8 days working 7 hours a day. If 2 persons join hem so as to complete the work in 4 days, they need to work per day for

**Q8.**Babu and Asha can do a job together in 7 days. Asha is 7/4 times as efficient as Babu. The same job can be done by Asha alone in

**Q9.**A wall of 100 meters can be built by 7 men or 10 women in 10 days. How many days will 14 men and 20 women take to build a wall of 600 meters?

**Q10.**A is 50% as efficient as B. C does half of the work done by A and B together. If C alone does the work in 20 days, then A, B and C together can do the work in

**Q11.**Some carpenters promised to do a job in 9 days but 5 of them were absent and remaining men were absent and remaining men did the job in 12 days. The original number of carpenters was

**Q12.**A contractor undertakes to make a road in 40 days and employs 25 men. After 24 days, he finds that only one third of the road is made. How many extra men should he employ so that he is able to complete the work 4 days earlier?

**Q13.**A can do a work in 5 days less than the time taken by B to do it. If both of them together take 100 /9 days, then the time taken by B’ alone to do the same work (in days) is

**Q14.**A, B and C can complete a work in 10, 12 and 15 days respectively. But A left the work before 5 days of its completion. B also left the work 2 days after A left. In how many days was the work completed?

**Q15.**5 men and 2 women working together can do four times as much work per hour as a man and a woman together. The work done by a man and a woman should be in ratio:

**Work and Time :: Answer Key**

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Please explain 11,13,14 problems of time and work

Q11. Let original men = M

M * 9 = (M-5)*12

3M= 60

M=20

Q13.: This question type you should always solve by using option. Very simple. Similar question came in 2014 Tier 1.

How ?

Took option C, try others they will not bring you 100/9

B A Let total work (LCM technique)

25 Days 20 days 100 units

1 day: 4 units 1 day: 5 units

Both A and B 1 day = 9 units So total time(days): 100/9

Note: Avoid x method in this case

Q14. . Let total work LCM of 10,12,15 = 60 units

A B C Total work

days 10 12 15 60 units

1 day work 6 units 5 units 4 units

Note: Trick: always start this variety from behind/ last

c works alone in last 3 days, so work 4*3 = 12 units

B & C work for 2 days =( 5+4) *2= 18 units

So last 5 days = 18+12 = 30 units.

It means 60-30= 30 units work happened initially which was done by A+B+C which they do in one day = 6+5+4= 15 units. So for 30 units these three in starting will take 30/15= 2 days.

Now total days

A+B+C B+C C

2 days 2 days 3 days = 7 days

Q 2 after lcm (60)

A+b = 5

B+c = 4

C+A = 3

How willl calculate days

Q2: Q2. A and B can do a work in 12 days, B and C in 15 days and C and A in 20 days. If A, B and C work together, they will complete the work in:

solve like this: Take total work 60 units ( LCM of 12, 15, 20)

A+ B 12 days work : 60 unit

A+ B 1 daywork 5 unit

B+ C 1 day work 4 unit

C+ A 1 day work 3 unit

A+B+ B+C+ C+A i.e. 2(A+B+C) 1 day work = 5+4+3 =12 unit

A+B+C 1 day work = 6 unit

Days work completed = 60/6 = 10 days

If any doubt, write to us.

Q9. A wall of 100 meters can be built by 7 men or 10 women in 10 days. How many days will 14 men and 20 women take to build a wall of 600 meters?

Q10. A is 50% as efficient as B. C does half of the work done by A and B together. If C alone does the work in 20 days, then A, B and C together can do the work in

please give me solution

How to solve Q. no. 5

Please explain question 9 plz….

Please provide the solution of ques 9 .. urgent

Q9. Solution

Q. A wall of 100 meters can be built by 7 men or 10 women in 10 days. How many days will 14 men and 20 women take to build a wall of 600 meters?

explanation:

7m = 10 w

14 m = 20 w

14 m & 20 women = 20 w+ 20 w = 40 w

Now given 10 w can built wall 100 meter in 10 days, then 600 m will be built in 60 days by these 10 w.

10 w built 600 m in = 60 days

1 w………………= 60*10

40 w………………= 60*10 divided by 40 = 15 days so option (a) is correct.

plz solve q.no.4,5

can someone solve question number 10 please

can someone solve question number 10 please urgent

Pls give solve of Number 15

Q.10 please solve

No need to solve qu 10 from starting….jst start from c’s work…1/2(1/A+1/B)=1\20….we will get the work of A and B for 1 day….then add 1 day work of C and of A and B….i.e 1 day work for A+B+C= 1/20+1/10

Q14. let Total work = T,

1 Man takes time to do work = M,

1 woman takes time to do work= W,

now

(5T/M+2T/W)=4*(T/M+T/W)…given

multipy both side by M

M/W=1/2.

so may be answer is b instead of a.

please reply and correct me if i am wrong.

thanks in advance

Please Post solution for Q.No 6.

Urgently

Thank You !

Sir how did u come to a conclusion stating ç worked only for 3 days

[youtube https://www.youtube.com/watch?v=9zAOc-AEGKo&w=640&h=360%5D

5 men and 2 women working together can do four times as much work per hour as a man and a woman together. The work done by a man and a woman should be in ratio: please give Please explain question 15

Please explain question .15

Guys help me how to solve problem no.12

i m very weak in maths so cudn’t solve ques 3 .pls anyone explain it.

if A is thrice efficient as B. and A will take 60 days less from B

than find out both work together…?

Now there is a simple short cut formula…

A+b+c = (one day work of a+b + one day work of b+c + one day work of c+d) divided by 2

Like..

A+b+c = 5+4+3/2 = 6

Now divide whole work with one day work

60/ 6 = 10

10 day is the ans.

question no, 7 how to solve please tell me

Please explain 10 no problem

sir i am unable to get advance maths 200 questions..can you please tell me where it is?

how to calucate q4

Hi Sir,

Can you please tell me the solution of question number 5 & 12?

Sir I want to purchase only math section study material what is the price ???

If English+Math then what is price???

Dear Reader,

Yes you can purchase the study material for maths section in Rs.4000. You may also buy this course using below mention link

https://www.instamojo.com/ssccgl/ssc-cgl-math-online-coaching-batch-starting-/

You can mail us at [email protected] or you may also call on +919729327755 for more information.

sir need help in question number 8

sir pls tell me abt 7 and 8 no question

qns no 7 – 5x8x7 = (5+2)x4xH

MDH= mdh formula

ans is 10 hrs

qns no 8 =

A B

Effe 7 4

Time 4 7

Than a take 11 days

qns no 8 =

A B

Effe 7 4

Time 4 7

Than a take 11 days

sir pls tell me abt 9 no question

14 men and 20 women are equal to 28 men hence:

(7*10)/1=(28*x)/6 (7 men can do work in 10 days then 28 men will do 6 times work in x days)

x=15

in the question no. 5 my answer is 4 days but this is wrong so how do you solve this question? kindly show me the steps

question no 2. my answer is a)-> 5 days. but answer is c). can you tell me which is right?

A- 3unit/day B= 2 unit/day. in 2 days- 5 unit. so required days= (30/5)X2= 12 days

10 days

a+b=12

b+c=15

c+a=20

LCM 60

work eff. 4 5 and 3 =12/2=6

60/6=10

if didn’t understand than go through the long method

Answer is 5days only,

@ hardeep i couldn’t get (work eff. 4 5 and 3 =12/2=6) this part of ur solution. Would you explain it ?

Plzz elaborate que.8

Ellaborate it more

solution of Q12?

1/3rd work requires 24*25 men days

therefore 2/3rd work will require = (24*25*3*2)/3 men days = 1200 men days (using unitary metod)

But we have to complete the work 4 days earlier which is 40-4 = 36

and workers has already worked for 24 days, therefore remaining days = 12 days

now suppose x men works daily for 12 days, then men days = 12 * x

which is equal to 1200 men days

12 * x = 1200

=> x = 100 men.

but because we already have 25 men , therefore we will need 100-25 = 75 men more

so answer is 75