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Advance Maths Series for SSC CGL Geometry- Day 2

Advance Maths Series for SSC CGL Geometry- Day 2

Dear Students, we have started “Advance Maths Series” for Maths. This mainly targets the Geometry part of the Advance Maths Syllabus. We are covering 10 questions of Geometry everyday.  This Article will cover Geometry- Day 2 questions.

Advance Maths has become a very important part of the SSC CGL examination. We have seen an increase in the number of questions from this section year after year. We expect 4-5 questions from the Geometry section in tier 1 and 9-11 questions in tier 2 of SSC CGL 2017. This is also one of the toughest part of Maths preparation. This section not only requires a firm understanding of the basics but also lots of practice to succeed in the examination. Advance Maths can be broadly divided into 4 parts: Mensuration, Algebra, Trigonometry and Geometry. This series will cover important questions of the Geometry section.

The Series will help in regular practice and to develop a good understanding of SSC CGL- Geometry.

Geometry- Day 2

Geometry- Day 2 Questions:

Q11. The circumcentre of a triangle ABC is O. If ∠BAC = 85° and ∠ACB =75°, then the value of ∠OAC is:

एक त्रिभुज ABC का परिकेन्द्र O है, ∠BAC = 85 ° और ∠OAC = 75 °, तो ∠OAB है:

(a) 40°

(b) 60°   

(c) 70°

(d) 90°

Q12. In ∆ ABC, D is the mid- point of BC. Length AD is 27 cm. N is a point in AD such that the length of DN is 12 cm. The distance of N from the centroid of ∆ ABC is equal to:

त्रिभुज ABC में, बिंदु D, BC का मध्य बिंदु है। AD की लंबाई 27 सेमी है। N, AD में एक बिंदु इस तरह है कि DN की लंबाई 12 सेमी है। त्रिभुज ABC के केन्द्रक से N की दूरी है:

(a) 3 cm

(b) 6 cm

(c) 9 cm

(d) 15 cm

Q13. The side BC of a triangle ABC is extended to D. If ∠ACD = 120° and ∠ABC = 12 ∠CAB, then       the value of ∠ABC is:

एक त्रिभुज ABC के भुजा BC को D तक बढ़ा दिया गया है तो ∠ACD = 120 डिग्री और ∠ABC = 1/2 ∠CAB, तो ∠ABC का मान है:

(a) 80°

(b) 40°  

(c) 60°

(d) 20°

Geometry- Day 2
Q14. In a ∆ ABC, If 2 ∠A = 3 ∠B = 6∠C, value of ∠B is:

त्रिभुज ABC में, अगर 2 ∠A = 3 ∠B = 6∠C, तब ∠B होगा:

(a) 60°

(b) 30°  

(c) 45°

(d) 90°

Q15. A tree of height ‘h’ metres  is broken by a storm in such a way that its top touches the ground at a distance of ‘x’ metres from its root. Find the height at which the tree is broken (Here h>x):

‘h’ मीटर ऊंचाई का एक पेड़ एक तूफान से इस तरह टूट गया है कि इसका सिरा अपनी जड़ से ‘x’ मीटर की दूरी पर जमीन को छू रहा है। ऊंचाई, जिस पर पेड़ टूट गया है (यहाँ h> x):

(a) h2+x22h metre  

(b) h2x22h metre

(c) h2+x24h metre

(d) h2x24h metre

Q16. In a ∆ ABC, the medians AD, BE and CF meet at G, then which of the following is true?

एक त्रिभुज ABC में, माध्यिका AD, BE और CF, G पर मिलते हैं, तो निम्न में से कौन-सा सही है?

(a) AD + BE + CF > 12 (AB + BC + AC)

(b) 2(AD + BE + CF) > (AB + BC + AC)

(c) 3(AD + BE + CF) > 4(AB + BC + AC)

(d) 4(AD + BE + CF) >3(AB + BC + AC)

Q17. The internal bisectors of the angles B and C of a triangle ABC meet at I. If ∠BIC = ∠A/2 + X, then X is equal to:

एक त्रिभुज ABC के कोण B और C के आंतरिक समद्विभाजक I बिंदु पर मिलते हैँ, अगर ∠BIC = (∠A)/2 + X, तो X बराबर है:

(a) 60°

(b) 30°   

(c) 90°

(d) 45°

Q18. The measure of the angle between the internal and external bisectors of an angle is:

एक कोण की आंतरिक और बाह्य समद्विभाजक के बीच के कोण का माप है:

(a) 60°  

(b) 70°   

(c) 80°

(d) 90°

Q19. AD is the median of a triangle ABC and O is the centroid such that AO = 10 cm. Length of OD (in cm) is:

AD किसी त्रिभुज ABC की माध्यिका है और O केन्द्रक है जिसमे AO = 10 सेमी है, OD (सेमी में) की लंबाई है:

(a) 2

(b) 4   

(c) 5

(d) 7

Q20. In a triangle ABC, median is AD and centroid is O. AO = 10 cm. The length of OD (in cm) is:

AD किसी त्रिभुज ABC की माध्यिका है और O केन्द्रक है जिसमे AO = 10 सेमी है, OD (सेमी में) की लंबाई है:

(a) 6

(b) 4

(c) 5

(d) 3.3

Geometry- Day 2 Solutions:

Geometry- Day 2
 

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