**Number System SSC CGL Math Project 400 Questions**

Number System SSC CGL Math Project 400 Questions

**About Project 400 Questions.**

I will post 400 MCQ on Maths for SSC-CGL. These 400 questions are unique. There are variety questions. I will call these questions as “Project 400 Questions”. These questions are developed on the basis of research. If any SSC CGL aspirant become proficient in these 400 questions I am sure he will score always 40+ score in maths in tier 1 and 180+ in tier 2. Keep in mind along with these representative questions a lot of practice is required.

**About Number System**

I am posting 20 varieties questions on ‘Number System’. This is considered as important chapter. Generally 4-5 questions can be asked in Tier 1 and 8-10 in Tier 2. This chapter will have direct link with other chapters also.

**Number System**

**Q1.**1/5 of a number exceeds 1/7 of the same number by 10. The number is:

a) 125 b) 150 c) 175 d) 200

**Q2.** Two numbers differ by 5. If their product is 336, the sum of the two numbers is:

a) 21 b) 28 c) 37 d) 51

**Q3.** Sum of two numbers is 40 and their product is 375. What will be the sum of their reciprocals?

a) 8/75 b) 1/40 c) 75/8 d) 75/4

**Q4.** Which of the following fractions is the smallest?

a) 9/13 b) 17/26 c) 28/29 d) 33/52

**Q5.** A number when divided by 899 gives a remainder 63. If the same number is divided by 29. The remainder will be:

a) 10 b) 5 c) 4 d) 2

**Q6.** The smallest number to be added to 1000, so that 45 divides the sum exactly is:

a) 35 b) 80 c) 20 d) 10

**Q7.**A six digit number is formed by repeating a three digit number; for example, 256, 256 or 678, 678 etc. Any number of this form is always exactly divisible by:

a) 7 only b) 11 only c) 13 only d) 1001

**Q8.** The sum of three consecutive odd natural numbers is 147, then, the middle number is:

a) 47 b) 48 c) 49 d) 51

**Q9.** The sum of all natural numbers between 100 and 200, which are multiples of 3 is:

a) 5000 b) 4950 c) 4980 d) 4900

**Q10.** How many digits in all are required to write numbers from 1 to 50? a) 100 b) 92 c) 91 d) 50

Number System

**Q11.** A number of friends decided to go on picnic and planned to spend Rs 108 on eatables. Three of them however did not turn up. As a consequence each one of the remaining had to contribute Rs 3 extra. The number of them who attended the picnic was:

a) 15 b) 12 c) 9 d) 6

**Q12.** The divisor is 25 times the quotient and 5 times the remainder. If the quotient is 16, the dividend is:

a) 6400 b) 6480 c) 400 d) 480

**Q13.** In a test, 1 mark is awarded for each correct answer and one mark is deducted for each wrong answer. If a boy answers all 20 items of the test and gets 8 marks, the number of questions answered correct by him was:

a) 16 b) 14 c) 12 d) 8

**Q14.** Of the three numbers, the second is twice the first and it is also thrice the third. If the average of three numbers is 44, the difference of the first number and the third number is:

a) 24 b) 18 c) 12 d) 6

**Q15.** A number when divided successively by 4 and 5 leaves remainders 1 and 4 respectively. When it is successively divided by 5 and 4 the respective remainders will be

a) 4,1 b) 3,2 c) 2,3 d) 1,2

**Q16:** The digit in unit’s place of the product 81 82 83 … … 89 is

a) 0 b) 2 c) 6 d) 8

**Q 17.** The sum of first sixty numbers from one to sixty is divisible by

a) 13 b) 59 c) 60 d) 61

**Q18.** The digit in the unit’s place of the product

(2464)^{1793 }^{ }^{ } (615)^{317 }(131)^{491 } is

a) 0 b) 2 c) 3 d) 5

**Q19.** (7^{19}^{ }+ 2) is divided by 6, the remainder is:

a) 5 b) 3 c) 2 d) 1

**Q20. ** 0.39393939………. is equal to

a) 39/100 b) 13/33 c) 93/100 d) 39/990

**Number System SSC CGL Math Project 400 Questions: Answer Key**

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First of all Hats off to ur efforts

I thnk if u provides way of solving these questions quickly, it will be very beneficial for us.

So plz if possible provide the solution also

Thnx

quick method for Q NO 15,16,17,18

When will the shortcuts and maths tricks be published for all topics??

q4 ans would be d

The coreect answer od Q4 is option d

Sir, please provide solution of ques no. 19

You can watch video of number system of these questions. https://www.youtube.com/watch?v=Gg0YqmXj5hM

You can join our online coaching batch. https://ssccglpinnacle.com/2449-2/

[…] Number System SSC CGL Math Project 400 Questions […]

Correct answer should be (b) for ques 19.

[…] Number System SSC CGL Math Project 400 Questions […]

can anyone tell me the solution of q15

https://youtu.be/Gg0YqmXj5hM?t=2692

answer to the question 4 is wrong

it should be “d”

as 33/52 is smaller than 9/13

9/13= 36/ 52 which is greater than 33/52.

[…] Number System SSC CGL Math Project 400 Questions […]

[…] Number System SSC CGL Math Project 400 Questions […]

[…] Number System SSC CGL Math Project 400 Questions […]

Q. 19 answer would be (b) 3 . just do 7+2/ 6 will gives 3 remainder

questn 4 answer is d

is question number 19’s answer in number system topic is wrong.

please check and response me faster.

Answers for question numbers 4 & 19 for Number system is given wrong.

yup… 19th answer is 3.

[…] Number System SSC CGL Math Project 400 Questions […]

[…] Number System SSC CGL Math Project 400 Questions […]

[…] Number System SSC CGL Math Project 400 Questions […]

[…] Number System SSC CGL Math Project 400 Questions […]

[…] Number System SSC CGL Math Project 400 Questions […]

[…] Number System SSC CGL Math Project 400 Questions […]

[…] Number System SSC CGL Math Project 400 Questions […]

[…] Number System SSC CGL Math Project 400 Questions […]

[…] Number System SSC CGL Math Project 400 Questions […]

[…] Number System SSC CGL Math Project 400 Questions […]

[…] Number System SSC CGL Math Project 400 Questions […]

answer of q 19 is wrong

answer of q 19&4 is wrong

plz explain q no 15

any short trick for q. 4

Answer to Q19 should be (b), that is, the remainder is 3.

9/13, 17/26, 33/52 can be written as 36/52, 34/52, 33/52. Obviously,33/52 is smallest among the three.Comparing 33/52 with 28/29. Now smaller the difference between numerator and denominator, higher will be the fraction. Hence 28/29 > 33/52.

Therefore, lowest fraction is 33/52.

Answer should be (d)

Answer : (c)

Let the number be N

Dividing this first by 4, we have :

N = 4Q + 1 — (i)

Bcoz the quotient from first division is divided by second number 5,

Q = 5X + 4 — (ii)

Substituting value of Q in (i),

=> N = 4(5X + 4) + 1

=> N = 20X + 17

=> N = (20X + 15) + 2

=> N = 5(4X + 3) + 2

If this number is divided by 5 first, the remainder is 2. Looking at the options, (c) is the only option where first remainder is 2.

Q5 : Let the number be ‘N’

Number = Divisor x Quotient + Remainder

N = 899Q + 63

N = (31 x 29)Q + (2 x 29) + 5

If this is now divided by 29, the remainder would be 5.

Q7 : Divisibility rule for 1001, 7, 11 & 13

1001 = 7 x 11 x 13

Take the number and group them into three digits starting from units place.

Take alternate groups and sum them.

Take the two sums and find their difference.

If the difference is divisible by 7, 11 or 13, the number is divisible by 7, 11 or 13.

Taking the number 256256, we group them as 256|256

Difference of the sum of the two alternate groups is 0 which is divisible by 1001, 7, 11 & 13.

Hence the number is always divisible by 7, 11, 13 & 1001.

Anser : Option (d)

Q14 : Let the second number = LCM(1,2,3) = 6

Then first number = 3 and third number is 2

Difference between first and third number = 3 – 2 = 1

Average of three numbers is (3+6+2)/3 = 11/3

If average = 11/3 ====> Difference = 1

If average = 1 ====> Difference = 1/(11/3) = 3/11

If average = 44 ====> Difference = 3/11 * 44 = 12

Answer : Option (c)

Q16 : 81 x 82 x 83 x 84 x 85 x ……….. x 89

In this series, we have 82 & 85 as two elements, the product of which is a multiple of 10 and will always end in 0. Therefore, the product of all 9 elements in the series will be a multiple of 10 and will always have units digits as 0.

Answer : Option (a)

Q20 : x = 0.39393939… (i)

100x = 39.39393939… (ii)

Subtracting (1) from (ii), we have :

99x = 39

x = 39/99 = 13×3/33×3 = 13/33

Answer : Option (b)

Short Cut :

-> See what number is repeating. It is 39.

-> See how many digits are repeating. It is 3 & 9 => 2 digits

-> Write repeating number in numerator and put as many 9s in denominator as the number of repeating digits. => 39/99

🙂

Q2 :

Since the two numbers differ by 5, the possible combinations of unit digits of two numbers can be :(1,6), (2,7),(3,8) & (4,9)

Since unit digits of the product of the two numbers is given as 6 ( units digit of 336 ), the only combinations possible is (1,6) or (4,9).

Taking sum of both combinations, the units place is either 7 or 3.

Looking at the options, only 37 satisfies the condition. There is no option where units digit is 3 🙂

Answer : Option (c)

Q4 :

9/13, 17/26, 33/52 can be written as 36/52, 34/52, 33/52.

Obviously,33/52 is smallest among the three.

Now Compare 33/52 with 28/29.

=> Now smaller the difference between numerator and denominator, higher will be the fraction.

Hence 28/29 > 33/52.

Therefore, lowest fraction is 33/52.

Answer should be (d)

Ya 19th ans is wrng .. correct ans is 3

sir, plzz explain q.9 and 11…