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Geometry Shortcut Formulas for SSC CGL Tier 1

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Geometry Shortcut Formulas for SSC CGL Tier 1

Geometry Shortcut Formulas for SSC CGL Tier 1

Basically Geometry topic plays an important role in every ssc examination and  questions are frequently asked in SSC exam which generally moderate to difficult. To help in your preparation we are providing you some useful shortcuts so that you can quickly solve the questions in minimum amount of time.

1.   In a ΔABC, If the bisectors of ∠B and ∠C meet at O then

∠BOC=90°+ 1/2∠A

  1.  In a ΔABC, If sides AB and AD are produced to D & E respectively and the bisectors of ∠DBC and ∠ECB intersects at O, then

∠BOC=90°- 1/2∠A

3. In a ΔABC, if AD is the bisector of ∠BAC & AE ⊥ BC, then,

∠BAE = 1/2(∠ABC-∠ACB)

4. In a ΔABC, if BC is produced to D and AE is the angle of bisector of In a ∠A, then

∠ABC∠ACD = 2∠AEC

5. In a right angle ΔABC∠B=90° and AC is hypotenuse. The Perpendicular BD is dropped on hypotenuse AC from right angle vertex B, then

  1. BD = (AB × BC)/AC
  2. AD = AB2/AC
  3. CD= BC2/AC
  4. 1/BD=(1/AB2)+ (1+BC2)