Simplification TCS Questions: SSC CGL Tier-1 2019

Simplification TCS Questions: SSC CGL Tier-1 2019

SSC CGL T-2 2019	SSC CGL T-1 2019	SSC CHSL 2019	SSC CPO 2020	SSC MTS 2019
SSC CGL T-2 2018	SSC CGL T-1 2018	SSC CHSL 2018	SSC CPO 2019	SSC MTS 2017

Q1. If ‘+’ means ‘-’, ‘-’ means ‘+’, ‘ × ’ means ‘ ÷ ’ and ‘ ÷ ’ means ‘ × ’ then the value of 

is:

यदि ‘+’ का अर्थ ‘-’, ‘-’ का अर्थ ‘+’, ‘×’ का अर्थ ‘ ÷ ’ तथा ‘ ÷ ’ का अर्थ ‘×’  है, तो का मान होगा 

SSC CGL 3 March 2020 (Morning)

(a) -5/3

(b) -151/9

(c) 15/19

(d) 5/3

Q3. The value of is equal to:

का मान किसके बराबर है?  

SSC CGL 3 March 2020 (Evening)

(a) -1/12

(b) -9/8

(c) -1/3

(d) -19/8

Q4. The value of is:

 का मान है : 

SSC CGL 3 March 2020 (Evening)

(a) 7 

(b) 1/7

(c) 7 ½ 

(d) 8 ½ 

Q5.  The value of  is:

 का मान है : 

SSC CGL 4 March 2020 (Morning)

(a) 26

(b) 25 ½ 

(c) 8 ½ 

(d) 24

Q6. The value of is:

का मान है : 

SSC CGL 4 March 2020 (Afternoon)

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Q7. The value of is:

 का मान है : 

SSC CGL 4 March 2020 (Evening)

(a) 17/8

(b) 8/3

(c) 16/170

(d) 2/17

Q8. The value of is:

का मान है : 

SSC CGL 5 March 2020 (Morning)

Q9. The value of 

का मान है : 

SSC CGL 5 March 2020 (Afternoon)

Q10. The value of 

का मान क्या होगा? 

SSC CGL 5 March 2020 (Evening)

(a) 2

(b) 5

(c) 17/4

(d) -7/2

Q11. If ‘+’ means ‘-’, ‘-’ means ‘+’, ‘ × ’ means ‘ ÷ ’ and ‘ ÷ ’ means ‘ × ’then the value ofis:

यदि ‘+’ का अर्थ ‘-’, ‘-’ का अर्थ ‘+’, ‘×’ का अर्थ ‘ ÷ ’ तथा ‘ ÷ ’ का अर्थ ‘×’  तो  का मान क्या होगा ? 

SSC CGL 6 March 2020 (Morning)

(a) 1

(b) -2

(c) 2

(d) -1

Q12.  Solve the following/ हल कीजिए :

4/3  ÷  1/6  ×  2-1= ?

SSC CGL 6 March 2020 (Afternoon)

(a) 8

(b) -2

(c) 3

(d) 15

Q13. Solve the following/ हल कीजिए :

113  ×  87 =?

SSC CGL 6 March 2020 (Afternoon)

(a) 10000

(b) 10169

(c) 10026

(d) 9831

Q14. The value of  is:

का मान क्या होगा?  

SSC CGL 6 March 2020 (Evening)

Q15. The value of 1512-1492 is: 

151² -149²  का मान है : 

SSC CGL 7 March 2020 (Morning)

(a) 300

(b) 400

(c) 2²

(d) 600

Q16. The value of 3-(9-3×8 ÷ 2) is:

3-(9-3×8 ÷ 2) का मान क्या होगा ?  

SSC CGL 7 March 2020 (Morning)

(a) -21

(b) 21/2

(c) 0

(d) 6

Q17. The value of is:

का मान होगा :  

SSC CGL 7 March 2020 (Afternoon)

Q18. Solve the following expression/ निम्नलिखित व्यंजक को हल कीजिए : 

5.6-{2+0.6 of (2.1-2.6 × 1.12)}

SSC CGL 7 March 2020 (Evening)

(a) 4.0871

(b) 4.0872

(c) 7.7112

(d) 7.7113

Q19. The value of 1800 ÷ 20 × {(12-6)+(24-12)} is:

1800 ÷ 20 × {(12-6)+(24-12)} का मान क्या होगा ?  

SSC CGL 9 March 2020 (Morning)

(a) 2720

(b) 1720

(c) 840

(d) 1620

Q20. Solve the following expression/ निम्नलिखित व्यंजक को हल कीजिए  

11+11 ×11-11 ÷ 11

SSC CGL 9 March 2020 (Afternoon)

(a) 121

(b) 22

(c) 11

(d) 131

Q21. The value of 515485 is: 

515 × 485 का मान है : 

SSC CGL 9 March 2020 (Evening)

(a) 249775

(b) 250225

(c) 20825

(d) 200825

Q22. The value of (26-13 × 2) ÷ 2+1 is:

(26-132)2+1 का मान है :  

SSC CGL 9 March 2020 (Evening)

(a) 0

(b) 1

(c) 263

(d) 14

Here are the solutions to the above questions of Simplification asked in the SSC exam by TCS. Some questions have alternate solutions.

Sol 1. (b) Replace symbols in equation  and apply BODMAS rule

Hence;

becomes = -1519 

Sol 2. (c) Apply BODMAS rule in the given equation:

Sol 3. (d)  On applying BODMAS rule in the given equation: 

We get , -5/2 +  3/2 ÷ 6 × 1/2= -19/8

Sol 4. (a) Apply BODMAS rule in the given equation

Sol 5. (b) Apply BODMAS rule in the given equation.

Sol 6. (b) On applying BODMAS rule,

Sol 7. (b) On applying BODMAS rule

Sol 8. (a) Apply BODMAS rule

Sol 9. (c) Apply BODMAS rule

Sol 10. (b) On Applying BODMAS 

 -1+1/4  ÷ 1/2 × 2+5 = 5

Sol 11. (b) 

As per given condition

Sol 12. (d) 4/3  ÷ 1/6 × 2-1=  4/3 × 6 × 2-1= 15

Sol 13. (d) As last digit of 113 × 87  is 1, only option (d) satisfies.

Sol 14. (a) (using BODMAS theorem)

Sol 15. (d) 151² -149² = (151-149)(151+149) = (2)(300) = 600

Sol 16. (d) 3-(9-3 × 8 ÷ 2) = 6 (using BODMAS theorem)

Sol 17. (b) Apply BODMAS

Sol 18. (b) Apply BODMAS theorem 

 5.6-{2+0.6 of (2.1-2.6  × 1.12)}  = 4.0872

Sol 19. (d) Apply BODMAS rule 

1800 ÷ 20 × {(12-6)+(24-12)} = 1620.

Sol 20. (d) Apply BODMAS rule or Digital sum rule in: 11+11  × 11-11 ÷ 11 = 131

Sol 21. (a) 515 × 485 = (500+15)(500-15) = 250000-225 = 249775

Sol 22. (b) Apply BODMAS rule 

(26-13 × 2) ÷ 2+1 = 1

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