Simplification TCS Questions: SSC CGL Tier-1 2019
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Simplification TCS Questions: SSC CGL Tier-1 2019
SSC CGL T-2 2019 | SSC CGL T-1 2019 | SSC CHSL 2019 | SSC CPO 2020 | SSC MTS 2019 |
SSC CGL T-2 2018 | SSC CGL T-1 2018 | SSC CHSL 2018 | SSC CPO 2019 | SSC MTS 2017 |
Q1. If ‘+’ means ‘-’, ‘-’ means ‘+’, ‘ × ’ means ‘ ÷ ’ and ‘ ÷ ’ means ‘ × ’ then the value of
is:
यदि ‘+’ का अर्थ ‘-’, ‘-’ का अर्थ ‘+’, ‘×’ का अर्थ ‘ ÷ ’ तथा ‘ ÷ ’ का अर्थ ‘×’ है, तो का मान होगा
SSC CGL 3 March 2020 (Morning)
(a) -5/3
(b) -151/9
(c) 15/19
(d) 5/3
Q3. The value of is equal to:
का मान किसके बराबर है?
SSC CGL 3 March 2020 (Evening)
(a) -1/12
(b) -9/8
(c) -1/3
(d) -19/8
Q4. The value of is:
का मान है :
SSC CGL 3 March 2020 (Evening)
(a) 7
(b) 1/7
(c) 7 ½
(d) 8 ½
Q5. The value of is:
का मान है :
SSC CGL 4 March 2020 (Morning)
(a) 26
(b) 25 ½
(c) 8 ½
(d) 24
Q6. The value of is:
का मान है :
SSC CGL 4 March 2020 (Afternoon)
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Q7. The value of is:
का मान है :
SSC CGL 4 March 2020 (Evening)
(a) 17/8
(b) 8/3
(c) 16/170
(d) 2/17
Q8. The value of is:
का मान है :
SSC CGL 5 March 2020 (Morning)
Q9. The value of
का मान है :
SSC CGL 5 March 2020 (Afternoon)
Q10. The value of
का मान क्या होगा?
SSC CGL 5 March 2020 (Evening)
(a) 2
(b) 5
(c) 17/4
(d) -7/2
Q11. If ‘+’ means ‘-’, ‘-’ means ‘+’, ‘ × ’ means ‘ ÷ ’ and ‘ ÷ ’ means ‘ × ’then the value ofis:
यदि ‘+’ का अर्थ ‘-’, ‘-’ का अर्थ ‘+’, ‘×’ का अर्थ ‘ ÷ ’ तथा ‘ ÷ ’ का अर्थ ‘×’ तो का मान क्या होगा ?
SSC CGL 6 March 2020 (Morning)
(a) 1
(b) -2
(c) 2
(d) -1
Q12. Solve the following/ हल कीजिए :
4/3 ÷ 1/6 × 2-1= ?
SSC CGL 6 March 2020 (Afternoon)
(a) 8
(b) -2
(c) 3
(d) 15
Q13. Solve the following/ हल कीजिए :
113 × 87 =?
SSC CGL 6 March 2020 (Afternoon)
(a) 10000
(b) 10169
(c) 10026
(d) 9831
Q14. The value of is:
का मान क्या होगा?
SSC CGL 6 March 2020 (Evening)
Q15. The value of 1512-1492 is:
1512 -1492 का मान है :
SSC CGL 7 March 2020 (Morning)
(a) 300
(b) 400
(c) 22
(d) 600
Q16. The value of 3-(9-3×8 ÷ 2) is:
3-(9-3×8 ÷ 2) का मान क्या होगा ?
SSC CGL 7 March 2020 (Morning)
(a) -21
(b) 21/2
(c) 0
(d) 6
Q17. The value of is:
का मान होगा :
SSC CGL 7 March 2020 (Afternoon)
Q18. Solve the following expression/ निम्नलिखित व्यंजक को हल कीजिए :
5.6-{2+0.6 of (2.1-2.6 × 1.12)}
SSC CGL 7 March 2020 (Evening)
(a) 4.0871
(b) 4.0872
(c) 7.7112
(d) 7.7113
Q19. The value of 1800 ÷ 20 × {(12-6)+(24-12)} is:
1800 ÷ 20 × {(12-6)+(24-12)} का मान क्या होगा ?
SSC CGL 9 March 2020 (Morning)
(a) 2720
(b) 1720
(c) 840
(d) 1620
Q20. Solve the following expression/ निम्नलिखित व्यंजक को हल कीजिए
11+11 ×11-11 ÷ 11
SSC CGL 9 March 2020 (Afternoon)
(a) 121
(b) 22
(c) 11
(d) 131
Q21. The value of 515485 is:
515 × 485 का मान है :
SSC CGL 9 March 2020 (Evening)
(a) 249775
(b) 250225
(c) 20825
(d) 200825
Q22. The value of (26-13 × 2) ÷ 2+1 is:
(26-132)2+1 का मान है :
SSC CGL 9 March 2020 (Evening)
(a) 0
(b) 1
(c) 263
(d) 14
Here are the solutions to the above questions of Simplification asked in the SSC exam by TCS. Some questions have alternate solutions.
Sol 1. (b) Replace symbols in equation and apply BODMAS rule
Hence;
becomes = -1519
Sol 2. (c) Apply BODMAS rule in the given equation:
Sol 3. (d) On applying BODMAS rule in the given equation:
We get , -5/2 + 3/2 ÷ 6 × 1/2= -19/8
Sol 4. (a) Apply BODMAS rule in the given equation
Sol 5. (b) Apply BODMAS rule in the given equation.
Sol 6. (b) On applying BODMAS rule,
Sol 7. (b) On applying BODMAS rule
Sol 8. (a) Apply BODMAS rule
Sol 9. (c) Apply BODMAS rule
Sol 10. (b) On Applying BODMAS
-1+1/4 ÷ 1/2 × 2+5 = 5
Sol 11. (b)
As per given condition
Sol 12. (d) 4/3 ÷ 1/6 × 2-1= 4/3 × 6 × 2-1= 15
Sol 13. (d) As last digit of 113 × 87 is 1, only option (d) satisfies.
Sol 14. (a) (using BODMAS theorem)
Sol 15. (d) 1512 -1492 = (151-149)(151+149) = (2)(300) = 600
Sol 16. (d) 3-(9-3 × 8 ÷ 2) = 6 (using BODMAS theorem)
Sol 17. (b) Apply BODMAS
Sol 18. (b) Apply BODMAS theorem
5.6-{2+0.6 of (2.1-2.6 × 1.12)} = 4.0872
Sol 19. (d) Apply BODMAS rule
1800 ÷ 20 × {(12-6)+(24-12)} = 1620.
Sol 20. (d) Apply BODMAS rule or Digital sum rule in: 11+11 × 11-11 ÷ 11 = 131
Sol 21. (a) 515 × 485 = (500+15)(500-15) = 250000-225 = 249775
Sol 22. (b) Apply BODMAS rule
(26-13 × 2) ÷ 2+1 = 1
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