Simplification TCS Questions: SSC CGL, CPO, CHSL, 2019

Simplification TCS Questions: SSC CGL, CPO, CHSL, 2019

Q1. The value of 2×3÷2 of 3×2(4 + 4×4÷4 of 4-4÷4×4) is:

2×3÷2 of 3×2(4 + 4×4÷4 of 4-4÷4×4) का मान ज्ञात करें | 

SSC CGL 4 June 2019 (Morning)

(a) 8

(b) 1                            

(c) 4

(d) 2

Q3. The value of (5+3÷5×5) / (3÷3 of 6) of (4×4÷4 of 4+4÷4×4) is

 (5+3÷5×5) / (3÷3 of 6) of (4×4÷4 of 4+4÷4×4) का मान ज्ञात करें |

SSC CGL 6 June 2019 (Morning)

(a) 8 1/5

(b) 7 1/3                  

(c) 9 3/5

(d) 6 2/3

Q4. The simplified value of

 is: 

सरलीकृत मान है

SSC CHSL 9 June 2019 (Evening)

(a) 1.0025

(b) 1.0525                

(c) 1.0005

(d) 1.0505

Q5. The value of 5÷5 of 5×2 + 2÷2 of 2×5 - (5-2)÷6×2 is: 

5÷5 of 5×2 + 2÷2 of 2×5 - (5-2)÷6×2 का मान ज्ञात करें |

SSC CGL 4 June 2019 (Afternoon)

(a) 9/5

(b) 19/10   

(c) 19

(d) 23/2

Q7. The value of 16 ÷ 4 of 4 ⨯ [ 3 ÷ 4 of { 4 ⨯ 3 ÷ ( 3 + 3 )}] ÷ (2 ÷ 4 of 8) is : 

16 ÷ 4 of 4 ⨯ [ 3 ÷ 4 of { 4 ⨯ 3 ÷ ( 3 + 3 )}] ÷ (2 ÷ 4 of 8)  का मान ज्ञात करें |

SSC CGL 6 June 2019 (Evening)

(a) 6

(b) 9                        

(c) 48

(d) 16

Q9. The value of 4.5 - ( 3.2 ÷ 0.8 ⨯ 5 ) + 3 ⨯ 4 ÷ 6 is

4.5 - ( 3.2 ÷ 0.8 ⨯ 5 ) + 3 ⨯ 4 ÷ 6 का मान ज्ञात करें |

SSC CGL 10 June 2019 (Afternoon)

(a) -13.5

(b) 4.2         

(c) -8.5

(d) 5.7

Q10. What is the simplified value of5÷10 of 10⨯4+4÷4 of 4⨯10-(10 -4)÷16⨯4

5÷10 of 10⨯4+4÷4 of 4⨯10-(10 -4)÷16⨯4 का सरलीकृत मान है-

SSC CHSL 3 July 2019(Evening)

(a) 1.2

(b) 2.5    

(c) 21

(d) 58.5

Q11. The simplified value of

is: 

का सरलीकृत मान है

SSC CHSL 5 July 2019(Afternoon)

(a) 13/64

(b) 13/16           

(c) 13/8

(d) 13/7

Q12. 

is equal to:

किसके बराबर है? 

SSC CPO 12 March 2019 (Evening)

(a) 0.009

(b) 0.0009                    

(c) 0.9

(d) 0.09

Q13. Find the value of

  का मान  क्या है ?

SSC CPO 14 March 2019 (Evening)

(a) 14

(b) 12.17               

(c) 4 

(d) 3.74

Here are the solutions to the above questions of Simplification asked in the SSC exam by TCS. Some questions have alternate solutions.

Sol 1. (d)

2⨯3÷2 of 3⨯2(4 + 4⨯4÷4 of 4-4÷4⨯4)

2⨯3÷6⨯2÷(4+4⨯4÷16-4÷4⨯4)

2⨯1/2 ⨯2⨯1 = 2

Sol 4. (b)

= 1.0525

Sol 6. (d)

Sol 7. (a)

Sol 9. (a) 

4.5 - ( 3.2 ÷ 0.8 ⨯ 5 ) + 3 ⨯ 4 ÷ 6 

4.5-(4⨯5)+2

6.5-20

= -13.5

Sol 10.(a)

Sol 11. (a)

Sol 13. (c) 

=4

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