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Number System TCS Questions For SSC CHSL 2021 Bilingual

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Number System TCS Questions For SSC CHSL  2021 Bilingual

SSC CGL Tier 2 2019 SSC CGL Tier 1 2019 SSC CHSL 2019 SSC CPO 2020 SSC MTS 2019
SSC CGL Tier 2 2018 SSC CGL Tier 1 2018 SSC CHSL 2018 SSC CPO 2019 SSC MTS 2017

Q1. If a 10-digit number 1220x558y2 is divisible by 88, then the value of (x + y) is:

यदि 10 अंकों की एक संख्या 1220x558y2, 88 से विभाजित है, तो (x+y) का मान क्या होगा?

SSC CHSL 4 July 2019 (Afternoon)

(a) 9       

(b) 7   

(c) 15

(d) 11

Q2. If a 10-digit number 6220x558y2 is divisible by 88, then the value of (5x+5y) is:

यदि 10 अंकों की एक संख्या 6220x558y2, 88 से विभाजित है, तो  (5x+5y) का मान क्या होगा ?

SSC CHSL 5 July 2019 (Morning)

(a) 20       

(b) 55  

(c) 25 

(d) 45

Q3. If a 10-digit number 7220x558y2 is divisible by 88, then the value of (5x + 5y) is:

यदि 10 अंकों की एक संख्या 7220x558y2   88 से विभाजित है, तो (5x + 5y) का मान ज्ञात करें |

SSC CHSL 5 July 2019 (Afternoon)

(a) 10        

(b) 25

(c) 15  

(d) 3 

Q4. If a 10-digit number 1230x558y2 is divisible by 88, then the value of (5x + 5y) is:

यदि 10 अंकों की एक संख्या 1230x558y2 , 88 से विभाजित है, तो (5x + 5y)  का मान ज्ञात करें|

SSC CHSL 5 July 2019 (Evening)

(a) 20       

(b) 40   

(c) 30

(d) 50

Q5. If an 8-digit number 30x558y2 is divisible by 88, then the value of (6x + 6y) is:

यदि 8 अंकों की संख्या 30x558y2   88 से विभाजित है, तो  (6x + 6y) का मान ज्ञात करें |

SSC CHSL 8 July 2019 (Morning)

(a) 42       

(b) 66     

(c) 30

(d) 35 

Q6. If the seven-digit number 54x29y6 (x > y) is divisible by 72, what is the value of (2x + 3y)?

यदि सात अंकों की संख्या 54x29y6 (x > y) 72 से विभाजित है, तो (2x + 3y) का मान क्या होगा ?

SSC CHSL 8 July 2019 (Evening)

(a) 32       

(b) 13   

(c) 38

(d) 23

Q7. If the seven digit number 64x29y6 (x > y) is divisible by 72, what is the value of (2x - 3y) ?

यदि सात अंकों की संख्या 64x29y6 (x > y)  72 से विभाजित है, तो (2x - 3y) का मान क्या होगा ?

SSC CHSL 9 July 2019 (Morning)

(a) 13       

(b) 3  

(c) 9

(d) 7

Q8. If the seven-digit number 64x29y6 (x > y) is divisible by 72, what is the value of (2x - y)?

यदि सात अंकों की संख्या 64x29y6 (x > y) 72 से विभाजित है, तो  (2x - y) का मान क्या होगा ? 

SSC CHSL 9 July 2019 (Afternoon)

(a) 3       

(b) 13   

(c) 7

(d) 9

Q9. The seven-digit number 78x1y68 is divisible by 88. The value of (x + y) is:

सात अंकों की संख्या 78x1y68     88 से विभाजित है | (x+y) का मान ज्ञात करें |

SSC CHSL 9 July 2019(Evening)

(a) 13       

(b) 10    

(c) 11    

(d) 14

Q10. The 10-digit number 79x00001y6 is exactly divisible by 88. What is the value of (x + y)?

10 अंकों की संख्या 79x00001y6     88 से पूर्णतः विभाजित है |  (x + y) का मान ज्ञात करें |

SSC CHSL 11 July 2019 (Afternoon)

(a) 5       

(b) 9

(c) 6      

(d) 7

Here are the solutions to the above questions of the number system in the short method. it will save you time in the exam.

Sol 1.

Ans. (a) 

1220x558y2 is divisible by 88, clearly, it will also be divisible by 11 and 8. For a number to be divisible by 11

(1+2+x+5+y)-(2+0+5+8+2) = 0 or 11

x+y-9 = 0 or 11

So, 

x+y = 9 or 20       

(but x and y can’t be more than 9 so their sum can’t be more than 18)

Clearly, 9 is the correct answer.

Sol 2.

Ans. (a)

6220x558y2 is divisible by 88, clearly, it will also be divisible by 11 and 8. For a number to be divisible by 11

(6+2+x+5+y)-(2+0+5+8+2) = 0 or 11

x+y-4 = 0 or 11

x+y = 4 or 15

Multiplying both sides by 5

5x+5y = 20 or 75

75 is not given in the options so 20 is the correct answer. 

Sol 3.

Ans. (c)

7220x558y2 is divisible by 88, clearly, it will also be divisible by 11 and 8. For a number to be divisible by 11

(7+2+x+5+y)-(2+0+5+8+2) = 0 or 11

x+y-3 = 0 or 11

x+y = 3 or 14

Multiplying both sides by 5

5x+5y = 15 or 70

70 is not given in the options so 15 is the correct answer. 

Sol 4.

Ans. (b)

1230x558y2 is divisible by 88, clearly it will also be divisible by 11 and 8. For a number to be divisible by 11

(1+3+x+5+y)-(2+0+5+8+2) = 0 or 11

x+y-8 = 0 or 11

x+y = 8 or 19       

(but x+y can’t be greater than 18)

Multiplying both sides by 5

5x+5y = 40  

Sol 5.

Ans. (a)

30x558y2 is divisible by 88, clearly, it will also be divisible by 11 and 8. For a number to be divisible by 11

(3+x+5+y)-(0+5+8+2) = 0 or 11

x+y-7 = 0 or 11

x+y = 7 or 18       

Multiplying both sides by 6

6x+6y = 42 or 108

108 is not given in the options clearly 42 is the right answer.

Sol 6.

Ans. (d)

54x29y6 is divisible by 72, clearly, it will also be divisible by 9 and 8. For a number to be divisible by 9, sum of its digits must be divisible by 9. 

5+4+x+2+9+y+6⇒26+x+y must be divisible by 9

Possible values of x+y = 1 or 10    …..(27 and 36 are multiples of 9)

For x+y =1, possible values of x and y are 1 and 0 respectively.     ..(x>y)

For x+y =7, possible values of x and y are (9,1), (8,2), (7,3), (6,4)    …(x>y)

Only for y=3, last three digits of the number are divisible by 8. Clearly, x=7 and y=3 are the desired values.

2x+3y = 2(7)+3(3) = 23 

Sol 7.

Ans. (b)

64x29y6 is divisible by 72, clearly, it will also be divisible by 9 and 8. For a number to be divisible by 9, sum of its digits must be divisible by 9. 

6+4+x+2+9+y+6⇒27+x+y must be divisible by 9

Possible values of x+y = 0 or 9 or 18        (27,36 and 45 are multiples of 9)

 x+y ≠0,     ..(x>y)

For x+y =9, possible values of x and y are (9,0),(8,1),(7,2),(6,3),(5,4)      …(x>y)

 x+y≠ 18, ….(x+y =18 possible only if x=y=9 but as per instructions x must be greater than y)

Only for y=3 last three digits of the number are divisible by 8. Clearly, x=6 and y=3 are the desired values.

(2x - 3y) = 2(6)-3(3) = 3

Sol 8.

Ans. (d)

64x29y6 is divisible by 72,  clearly, it will also be divisible by 9 and 8. For a number to be divisible by 9, sum of its digits must be divisible by 9. 

6+4+x+2+9+y+6⇒27+x+y must be divisible by 9

Possible values of x+y = 0 or 9 or 18        (27,36 and 45 are multiples of 9)

 x+y≠ 0,     ..(xy)

For x+y =9, possible values of x and y are (9,0),(8,1),(7,2),(6,3),(5,4)      …(x>y)

 x+y ≠18, ….(x+y =18 possible only if x=y=9 but as per instructions x must be greater than y)

Only for y=3, last three digits of the number are divisible by 8. Clearly, x=6 and y=3 are the desired values.

(2x - y) = 2(6)-3 = 9

Sol 29. (c) 78x1y68 is divisible by 88, clearly, it will also be divisible by 11 and 8.

For a number to be divisible by 11

(7+x+y+8)-(8+1+6) = 0 or 11

x+y = 0 or 11

For x+y = 0, x=y=0

But for y=0 last three digits of the number are not divisible by 8. Clearly, x+y = 11 is the desired answer. 

Sol 10.

Ans. (b)

79x00001y6 is divisible by 88, clearly it will also be divisible by 11 and 8.

For a number to be divisible by 11

(7+x+0+0+y)-(9+0+0+1+6) = 0 or 11

x+y -9 = 0 or 11

x+y = 9 or 20        (but x+y can’t be 20 as x and y can’t exceed 9)

Clearly x+y = 9 is the desired answer.

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